Updated Nov.17/04 ----------------------------------------------------------------------------------------- NUMERICAL ANSWERS TO ASSIGNED TUTORIAL PROBLEM SETS FOR CHEM206 FROM KOTZ & TREICHEL'S CHEMISTRY & CHEMICAL REACTIVITY ----------------------------------------------------------------------------------------- NOTE: not all answers have been verified. SO FAR: checked up to Ch.19 #29 NOTE: "^" means "raised to the power of..." to indicate scientific notation Ch. Q# Ans. Units SFs Comments ----------------------------------------------------------------------------------------- 19 13a impure Si 19 13b O2(g) at 0C 19 13c iodine gas 19 13d at lower P 19 19 -99.1 J/K 3 19 23 -15.4 J/K 3 19 27 318.9 J/K 4 delta-S universe > 0 --> spontaneous 19 29 spontaneous at all temperatures 19 29 favoured at high temperatures 19 33a -431.16 kJ 5 delta-H 19 33a -125.3 J/K 4 delta-S 19 33a -393.8 kJ 5 delta-G <0;product favoured (fwd rxn is spontaneous); enthalpy-driven 19 33b 49.03 kJ 4 delta-H 19 33b -252.4 J/K 4 delta-S 19 33b 124.3 kJ 4 delta-G >0;reverse is spontaneous; driven in reverse by both H & S 19 37a -249.5 kJ 4 product-favoured 19 37b -990.32 kJ 5 product-favoured 19 41a 100.89 J/K 5 entropy-favoured;higher T --> more products 19 41b -187.95 J/K 5 entropy-disfavoured;higher T --> more reactants… 19 41c 315.5 J/K 4 entropy-favoured;higher T --> more products note: SiCl4 is (g), not (l) 19 41d 15.7 J/K 3 entropy-favoured; higher T --> more products 19 43 2141 K 4 this T or higher is necessary 19 45 2.5x10^-29 2 this is Kp --> << 1, means reactants dominate at eqm large +ve delta-G (non-spontaneous fwd; spont. reverse!) 19 47 4.0x10^14 2 large Kp value --> products dominate at eqm matches large -ve delta-G (spontaneous fwd rxn) 19 49 -125.52 kJ 5 delta-H 19 49 -129.9 J/K 4 delta-S 19 49 -86.81 kJ 4 delta-G --> negative; product-favoured under std. conditions 19 51 -352.88 kJ 5 delta-H 19 51 21.31 J/K 4 delta-S(sys) 19 51 1205 J/K 4 delta-S(univ) --> positive, spontaneous fwd. 19 53a 117 kJ/mol 3 delta-G (std states)...determined using delta-G=(delta-H)-Tx(delta-S) calculated via...delta-S(sys)=216.53 J/K; delta-H=181.66 kJ delta-S(surr)=-609.6 J/K from delta-H. delta-S(univ)=-393.1 J/K 53b 3.1x10^-21 2 Kp is very small, therefore reactant favoured 19 55a 2.8 kJ 2 delta-G --> positive;rxn does not occur on its own… 19 55b high T,P used to overcome unfavourable thermodynamics 19 69a + + + 19 69b - + - 19 69c - + - 19 73 6.98 kJ/mol 3 delta-G(rxn) at std states calculated via -RTlnK 19 77a 91.42 kJ 4 delta-G(rxn, std) calculated from thermo. data 77b 9.5x10^-17 2 eqm constant K; for 298K using delta-G=-RTlnK 77c 707.3 degrees C 4 temp where delta-G=0 (eqm for std state concentrations) 19 79a 161.61 J/K 5 delta-S > 0 matches liquid --> gases 19 79b 115.3 kJ 4 delta-G > 0 therefore non-spont. (ie, reverse rxn is spont.) 19 79c 739 C 3 lowest T at which fwd rxn is spontaneous 19 87a O2 = oxidizing agent; N2H4 = reducing agent 19 87b -623.77 kJ 5 delta-G < 0 therefore spontaneous 19 89 -10.9 kJ/mol 3 delta-G(std) calcd for 623K using Kp=8.16 & -RTlnK...